The insulated plates of a parallel plate capacitor has a charge density `sigma`. Show that that the work done in changing the distance from `d_(1)` to `d_(2)` is

The plates of a parallel plate capacitor are not exactly parallel. The surface charge density is therefore,

The plates of a parallel plate capacitor are, not exactly parallel. The surface charge density therefore :

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )

The plates of a parallel plate capacitor are charged with a battery so that the plates of the capacitor have acquired the P.D. equal to e.m.f of the battery. The ratio of the work done by the battery and the energy stored in capacitor is

In the figure shown the plates of a parallel plate capacitor have unequal charges. Its capacitance is 'C' P is a point outside the capacitor and close to the plate of charge -Q . The distance between the plates is 'd'