In a triangle ABC, if `cot""A/2 cot""B/2=c, cot""B/2 cot""C/2=a` and `cot""C/2 cot""A/2=b`, then `1/(s-a)+1/(s-b)+1/(s-c)=`

In a triangle ABC,if a cot A+b cot B+c cot C=

In a DeltaABC , if cot.(A)/(2)cot.(B)/(2)=c , cot.(B)/(2)cot.(C )/(2)=a and cot.(C)/(2)cot.(A)/(2)=b , then (1)/(s-a)+(1)/(s-b)+(1)/(s-c) equals

In triangle ABC, the value of (cot""A/2cot ""B/2-1)/(cot ""A/2 cot ""B/2) is

In Delta ABC, if s=2b then cot""A/2 cot ""C/2 =

In triangle ABC the value of ( cot A/2 cot ""B/2 -1)/( cot""A/2 cot""B/2) is

In Delta ABC, cot ""(A)/(2) +cot""(B)/(2) + cot""(C)/(2)=

In Delta ABC, if cot""A/2:cot""B/2:cot""C/2=3:7:9 , then a:b:c=

In any triangle ABC prove that cot(A/2)+cot(B/2)+cot(C/2)=cot(A/2)cot(B/2)cot(C/2)