The velocity of particle at time t is given by the relation `v=6t-(t^(2))/(6)`. The distance traveled in 3 s is, if s=0 at t=0

The distance S (in kms ) travelled by a particle in time t hours is given by S (t) =( t^(2)+3t)/( 2) The distance travelled in 3 hrs .

The position of a body moving along x-axis at time t is given by x= (t^(2)-4t+6)m . The distance travelled by body in time interval t = 0 to t = 3 s is

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = 1 s will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = t will be :

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the velocity at t=2 sec

the velocity of a particle varies with time as shown below the distance travelled by the travelled by the particle during t=2s"and" t= 6s. Is

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

The distance s moved by a particle in time t is given by s=t^(3)-6t^(2)+6t+8 . When the acceleration is zero, the velocity is ………..

The distance s of a particle in time t is given by s=t^3-6t^2-4t-8 . Its acceleration vanishes at t=