In a LR circuit, the AC source has voltage 220V and potential difference across the resistor is 176V .The power factor of the circuit is

In L-R circit, the A.C. source has voltage 220V . If potential difference across inductor is 176V , the potential difference across the resistor (in Volts) is Kxx33 . Find the value of K

In L-R circuit, the a.c. source has voltage 220 volt. If the potential difference across the inductance is 176 volt, the p.d. across the resistance will be

Assertion: An inductance and a resistance are connected in series with an AC circuit. In this circuit the current and the potential difference across the resistance lag behind potential difference across the inductance by an angle pi//2 . Reason: In LR circuit voltage leads the current by phase angle which depends on the value of inductance and resistance both.

In a series LR circuit, the voltage drop across inductor is 8 volt and across resistor is 6 volt. Then voltage applied and power factor of circuit respectively are:

An electrical heater and a capacitor are joined in series across a 220V, 50Hz, AC supply. The potential difference across the heater is 90V . The potential difference across the capacitor will be about:

An 220V AC voltage at a frequency of 40 cycles/s is applied to a circuit containing a pure inductance of 0.01H and a pure resistance of 6 Omega in series. Calculate (a) The current supplied by source (b) The potential difference across the resistance (c ) The potential difference across the inductance (d) The time lag between maxima of current and EMF in circuit

What is the value of power factor for series LR circuit ?

In the given LR circuit the source has angular frequency omega The power factore of the circuit is .

In the circuit, V is potential differences across the terminal as shwon in figure. Then the value of V is