In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

In the adjacent figure ( not to scale), O is the centre of the circle and /_OBA =30^(@) . Find /_ ACB . The following sentences ae the steps involved in solving the above problem. Arrange them in sequential order from the first to the last. (A) /_OAB =30^(@), /_ OBA =30^(@) implies /_ AOB =180^(@) -30^(@)-30^(@) =120^(@) (B) We known that /_ ACD =("Reflex "/_AOB)/(2)=(240^(@))/(2)=120^(@) (C ) Reflex /_ AOB =240^(@) (D ) OA =OB (radii) implies /_ OBA= /_ OAB =30^(@) .

In Figure,O is the centre of the circle.Find /_BAC

O is the centre of the circle /_BCO=30^(@) then find x and y

In Figure, O is the centre of the circle. Find /_B A C

In Figure,O is the centre of the circle.Find /_CBD

In figure, O is the centre of the circle angleBCO=30^(@) . Find X and Y.