At a height of 0.4 m from the ground, the velocity of projectile in vector from is `vec(u)=(6hat(i)+2hat(j))` (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is : `(g = 10 m//s^(2))`

A particle is projected from gound At a height of 0.4 m from the ground, the velocity of a projective in vector form is vecv=(6hati+2hatj)m//s (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is (g=10m//s^(2))

A particle is projected from gound At a height of 0.4 m from the ground, the velocity of a projective in vector form is vecv=(6hati+2hatj)m//s (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is (g=10m//s^(2))

At a height 0.4 m from the ground the velocity of a projectile in vector form is vec v = (6 hat i+ 2 hat j) ms ^-1 . The angle of projection is

At a height 0.4 m from the ground the velocity of a projectile in vector form is vec v = (6 hat i+ 2 hat j) ms ^-1 . The angle of projection is

Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Angle of projectile with ground is

Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Angle of projectile with ground is

The angle made by the vecotr vec(A)= hat(i)+hat(j) with x-axis is

Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Maximum height from a ground is …….. m

Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Maximum height from a ground is …….. m