`cosecx\ logy(dy)/(dx)+x^2y^2=0`

Solve the differential equation "cosec"x logy(dy)/(dx) + x^(2)y^(2)=0.

Solve the differntial equations: cosecx log y dy+x^2y^2dx=0

(dy)/(dx)+(x-2y)/(2x-y)=0

y dx+(x-y^2)dy=0

Verify that the given function (implicit or explicit) is a solution of the corresponding differential equation: x^2 = 2y^2 (logy) : (x^2 + y^2)((dy)/(dx)) - xy = 0

An integrating factor of the differential equation ylogy(dx)/(dy)+x-logy=0 , is

The integrating factor of the differential equation ylogy(dx)/(dy)+x-logy=0 , is

For each of the exercises given below, verify that the given function ( implicit or explicit ) is a solution of the corresponding differential equation. x^(2)=2y^(2)logy:(x^(2)+y^(2))(dy)/(dx)-xy=0

The solution of the differential equation (dy)/(dx)=(x^2+x y+y^2)/(x^2), is a.) tan^(-1)(x/y)=logy+C b.) tan^(-1)(y/x)=logx+C c.) tan^(-1)(x/y)=logx+C d.) tan^(-1)(y/x)=logy+C

Solve ((dy)/(dx))^2-x(dy)/(dx)+y=0