A particle performs SHM with an amplitude of 5 m. If at x = 4 m, the magnitude of velocity and accelertion are equal, then the time period of SHM (in seconds) is

A particle is executing SHM with an amplitude of 2 m. The difference in the magnitudes of its maximum acceleration and maximum velocity is 4. The time period of its oscillation is

A particle performs S.H.M. with amplitude 5 m, period 0.02 . s and x = 2.5 m at t = 0. Which is the correct equation?

A particle performs S.H.M. with amplitude 5 m, period 0.02 . s and x = 2.5 m at t = 0. Which is the correct equation?

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude the time period will be

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be

The graph between instantaneous velocity and acceleration of a particle performing S.H.M. is