[" A gram mole of a gas at "127^(@)C],[" expands isothermally until its volume is doubled.Find the amount of work done."]

A gram molecule of a gas at 127^(@)C expands isothermally until its volume is doubled. Find the amount of work done and heat absorbed.

A gram molecule of a gas at 127^(@)C expands isothermally until its volume is doubled. Find the amount of work done and heat absorbed.

One gram mole of oxygen gas at 127^@C expands isothermally until its volume is doubled. Find the amount of work done and heat produced R=8.314"jmole"^-1k^-1

A gram molecule of gas at 27^(@)C expands isothermally untill its volume is doubled. Find the amount of work done and heat absorbed. Take R=8.31J mol e^(-1) K^(-1) .

A gram mole of a gas at 27^@C expands isothermally until its volume is doubled. Calculate the amount of work done. (R=8 J mol^(-1) K^(-1))

A gm molecule of a perfect gas at 100^@C expands isothermally until its volume is doubled. Find the amount of work done and the heat absorbed. R = 8.3J//gm-mol//K .

Three moles of an ideal gas at 127^(@)C expands isothermally untill the volume is doubled. Calculate the amount of work done and heat absorbed.

A certain volume of a gas (diatomic) expands isothermally at 20^@C until its volume is doubled and then adiabatically until its volume is again doubled. Find the final temperature of the gas, given gamma = 1.4 and that there is 0.1 mole of the gas. Also calculate the work done in the two cases. R=8.3 J "mole"^(-1) K^(-1)

If x mole of ideal gas at 27^(@)C expands isothermally and reversibly from a volume of y to 10 y, then the work done is