A solid cylinder of mass 2kg rolls down (pure rolling) an inclined plane from a height of 4m. Its rotational kinetic energy, when its reaches the foot of the plane is (Take g=10m`s^(-2))`

A solid cylinder, of mass 2 kg and radius 0.1 m, rolls down an inclined plane of height 3m. Calculate its rotational energy when it reaches the foot of the plane.

A disc of mass 3 kg rolls down an inclined plane of height 5 m. The translational kinetic energy of the disc on reaching the bottom of the inclined plane is

A disc of mass 3 kg rolls down an inclined plane of height 5 m. The translational kinetic energy of the disc on reaching the bottom of the inclined plane is

Assertion: A solid cylinder of mass m and radius r rolls down an inclined plane of height H. The rotational kinetic energy of the cylinder when it reaches the bottom of the plane is mgH/3. Reason: The total energy of the cylinder remains constant throughout its motion.

A solid sphere of mass m rolls down an inclined plane a height h . Find rotational kinetic energy of the sphere.

A solid sphere of mass m rolls down an inclined plane a height h . Find rotational kinetic energy of the sphere.

A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

A solid cylinder rolls down an inclined plane from a height h. At any moment the ratio of rotational kinetic energy to the total kinetic energy would be