A layer of ice 2 cm thick is formed on a pond. The temperature of air is `-20^(@)C`. Calculate how long it will take for the thickness of ice to increase by 1mm. Density of ice `= 1g cm^(-3)`. Latent heat of ice `= 80 cal g^(-1)`. Conductivity of ice `= 0.008 cal s^(-1) cm^(-1) .^(@)C^(-1)`.

On the Dal lake of Kashmir, a layer of 2 cm thick ice is formed when the outside temperature is -10^@C . How much time it will take for the increase in thickness of ice by 0.5 mm? Take, Density of ice = 1 g//c^3 m Latent heat of ice = 80 cal/g Thermal conductivity of ice = 0.008 cal s^(-1) cm^(-1) ""^@C^(-1)

An ice layer of thickness 3 cm is formed on a lake. How much time will it take to increase the thickness of ice by 2 mm if temperature of air is -30^@C ? Take, Density of ice = 1 g cm^(-3) , Latent heat of ice = 80 cal g^(-1) , Conductivity of ice = 0.008 cal s^(-1) cm^(-1) ""^@C^(-1)

A layer of ice 29 cm thick has formed on a pond. The temperature of air is -10^(@)C . Find how long will it take for another 0.1 cm layer of water to freeze? Conductivity of ice = 2.1 J s^(-1)m^(-1)K^(-1) . Latent heat capacity of ice =3.36 xx 10^(5) J kg^(-1) and density of ice = 1000 kg m^(-3) .

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )

A layer of ice 0.15 m thick has formed on the surface of a deep pond. If the temperature of upper surface of ice is constant and equql to that of air which is -12^(@)C , determine the time it will take to increase of ice layer by 0.2 mm. take latent heat of ice =80 cal g^(-1) , density of ice =0.91 g cm^(-3) and thermal conductivity of ice =0.5 cal s^(-1)m^(-1)K^(-1) .

The thickness of ice on a Jake is 6 cm and the temperature of air is - 10^(@) C . At what rate is the thickness of ice increasing ? Thermal conductivity of ice = 2 "Wm"^(-1) "K"^(-1) . Density of ice = 920 "kg m"^(3) , specific latent heat of ice = 336 "KJ kg"^(-1)

If a ball of 80 kg mass hits an ice cube and temperature of ball is 100 .^(@)C , then how much ice converted into water ? (Specific heat of ball is 0.2 cal g^(-1) , Latent heat of ice = 80 cal g^(-1) )

If a ball of 80 kg mass hits an ice cube and temperature of ball is 100 .^(@)C , then how much ice converted into water ? (Specific heat of ball is 0.2 cal g^(-1) , Latent heat of ice = 80 cal g^(-1) )