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Temperature of 100 gm water is changed f...

Temperature of 100 gm water is changed from `0^@C " to " 3^@C` . In this process , heat supplied to water will be (specified heat of water `1 cal g^(-1) .^@C^(-1))`

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If 2000kg of water is heated from 0^(@) C to 100^(@)C , what will be the corresponding increase in mass of water? Take specific heat of water =1cal. g^(-1).^(@)C^(-1) .

10 gram of water at 45^(@)C is added to 5 gram of ice at -30^(@)C . Find the final temperature of the mixture. Specific heat of ice is 0.55 cal g^(-1)""^(@)C^(-1) and that of water is 1.0 cal g^(-1)""^(@)C^(-1) latent heat of fusion of ice is 80 cal g^(-1) ? (ii) To rise the temperature of 100 gram of water from 24^(@) to 90^(@)C by steam at 100^(@)C . Calculate the amount of steam required. Specific heat of water is 1.0 cal g^(-1)""^(@)C^(-1) . Latent heat of steam is 540 Cal kg^(-1) .

Stream at 100^(@)C is passed into 20 g of water at 10^(@)C . When water acquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of steam =540 cal g^(-1) ]

Stream at 100^(@)C is passed into 20 g of water at 10^(@)C . When water acquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of steam =540 cal g^(-1) ]

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

Steam at 100^@C is passed into 20 g of water at 10^@C When water acquires a temperature of 80^@C , the mass of water present will be Take specific heat of water= 1 cal g^-1^@ C^-1 and latent heat of steam = 540 cal g^-1 )

A sample of 100 gm of water is slowly heated from 27^(@)C to 87^(@)C . Calculate the change in the entropy of water. Specific heat capacity of water = 4200 J cdot kg^(-1) cdot K^(-1)