`S_(("rhombic"))+O_(2(g))rarr SO_(2(g)) , Delta H =-297.5 K J`
`S_(("monoclinic"))+O_(2(g))rarr SO_(2) , Delta H = - 300 K J`
The data can predict that -

S( rhombic ) + O_(2) rarr SO_(2)," " DeltaH=-297.5kJ S( monoclini ) + O_(2) rarr SO_(2), " "DeltaH=-300kJ This date indicates :

Given C_((s)) + O_(2(g)) rarr CO_(2(g)), Delta H = -395 kJ , S_((g)) + O_(2(g)) rarr SO_(2(g)) , Delta H = -295 kJ , CS_(2(l)) + 3O_(2(g)) rarr CO_(2(g)) + 2SO_(2(g)) , Delta H = -1110 kJ The heat of formation of CS_(2(l)) is

Given C_((s)) + O_(2(g)) rarr CO_(2(g)), Delta H = -395 kJ , S_((g)) + O_(2(g)) rarr SO_(2(g)) , Delta H = -295 kJ , CS_(2(l)) + 3O_(2(g)) rarr CO_(2(g)) + 2SO_(2(g)) , Delta H = -1110 kJ The heat of formation of CS_(2(l)) is

Consider the reactions (i) S (rhombic) + 3//2O_(2) (g) rarr SO_(3) (g), Delta H_(1) (ii) S (monoclinic) +3//2O_(2) (g) rarr SO_(3) (g), Delta H_(2) (iii) S(rhombic) +O_(3) (g) rarr SO_(3) (g) , Delta H_(3) (iv) S (monoclinic) +O_(3)(g) rarr SO_(3) (g), Delta H_(4) incorrect statement is

Using the following thermochemical equations : S("rhombic") + 3/2 O_(2)(g) rarr SO_(3)(g), " "Delta H = - 2x kJ mol^(-1) II. SO_(2)(g) + 1/2 O_(2)(g) rarr SO_(3)(g), " "Delta H = -Y kJ mol^(-1) Find out the heat of formation of SO_(2)(g) in kJ mol^(-1) .