यदि `a_(1), a_(2), ……., a_(n)` स. श्रे. में हों, तो दिखाओं कि
`(1)/(sqrt(a_(1))+sqrt(a_(2)))+(1)/(sqrt(a_(2))+sqrt(a_(3)))+....+(1)/(sqrt(a_(n-1))+sqrt(a_(n)))=(n-1)/(sqrt(a_(1))+sqrt(a_(n)))`.

If a_(1) ge 0 for all t and a_(1), a_(2), a_(3),….,a_(n) are in A.P. then show that, (1)/(sqrt(a_(1))+sqrt(a_(2)))+(1)/(sqrt(a_(2))+sqrt(a_(3)))+ (1)/(sqrt(a_(n-1))+sqrt(a_(n))) = (n-1)/(sqrt(a_(1))+sqrt(a_(n)))

If a_(1), a_(2), a_(3),……,a_(n) are in AP, where a_(i) gt 0 for all i, show that (1)/(sqrt(a_(1)) + sqrt(a_(2))) + (1)/(sqrt(a_(2)) + sqrt(a_(3))) + …..+ (1)/(sqrt(a_(n-1))+ sqrt(a_(n)))= (n-1)/(sqrt(a_(1)) + sqrt(a_(n)))

If a_(1), a_(2), a_(3),…..a_(n) are in A.P where a_(i) gt 0, AA I then (1)/(sqrt(a_(1)) + sqrt(a_(2))) + (1)/(sqrt(a_(2)) + sqrt(a_(3)))+ …+ (1)/(sqrt(a_(n-1)) + sqrt(a_(n))) = (k)/(sqrt(a_(1)) + sqrt(a_(n))) then k=

If a_(1),a_(2),a_(3),a_(n) are in A.P,where a_(i)>0 for all i, show that (1)/(sqrt(a_(1))+sqrt(a_(2)))+(1)/(sqrt(a_(2))+sqrt(a_(3)))++(1)/(sqrt(a_(n-1))+sqrt(a_(n)))=(n-1)/(sqrt(a_(1))+sqrt(a_(n)))

If a_(1), a_(2), a_(3), a_(4) are in AP, then (1)/(sqrt(a_(1)) + sqrt(a_(2))) + (1)/(sqrt(a_(2)) + sqrt(a_(3))) + (1)/(sqrt(a_(3)) + sqrt(a_(4))) is equal to

If a_(1),a_(2),a_(3)... are in A.P then prove that (1)/(sqrt(a)_(1)+sqrt(a)_(2))(+)/(sqrt(a)_(2)+sqrt(a)_(3))+...+(1)/(sqrt(a)_(n-1)+sqrt(a)_(n))=(n-1)/(sqrt(a)_(n)+sqrt(a)_(1))

If a_(1), a_(2) …… a_(n) are in A.P then (sqrt(a_(1)) + sqrt(a_(n)))/( sqrt(a_(1)) + sqrt(a_(2))) + (sqrt(a_(1)) + sqrt(a_(n)))/(sqrt(a_(2)) + sqrt(a_(3))) + ….. + (sqrt( a_(1)) + sqrt(a_(n)))/( sqrt(a_(n - 1)) + sqrt(a_(n))) =

If a_(r ) gt 0, r in N and a_(1), a_(2) , a_(3) ,"……..",a_(2n) are in A.P. then : (a_(1) + a_(2n))/( sqrt( a_(1))+ sqrt(a_(2))) + ( a_(2) + a_(2n-1))/(sqrt(a_(2)) + sqrt(a_(3)))+"......"(a_(n)+a_(n+1))/(sqrt(a_(n))+sqrt(a_(n+1))) is equal to :