" (ii) दिखायें कि "sin(50^(@)+theta)-cos(40^(@)-theta)=0" ."

Prove that (i) " sin " (50^(@) + theta ) " cos " (20^(@) + theta) - " cos " (50^(@) + theta) " sin " (20^(@) + theta) =(1)/(2) (ii) " cos " (70^(@) + theta ) " cos " (10^(@) + theta ) + " sin " (70^(@) + theta) " sin " (10^(@) + theta)=(1)/(2)

Solve cos(50^(@)+ theta) = sin (30^(@)+theta) .

Prove that (i) sin(40^(@)-theta)-cos(50^(@)+theta)=0 (ii) sec(65^(@)+theta)-"cosec"(25^(@)-theta)=0

Prove that (i) sin(40^(@)-theta)cos(50^(@)+theta)=0 (ii) 1sec(65^(@)+theta)-"cesec"(25^(@)-theta)=0

Show that: sin (40^(@) + theta) cos (10^(@) + theta) -cos(40^(@) + theta) sin (10^(@) + theta) = (1)/(2)

The value of {cos(40^(@)+theta)-sin(50^(@)-theta)} is

If sin(50^@-((3theta)/2))=cos(3theta-50^@)

sin theta -cos theta=0

The value of cos(40^@+theta)-sin(50^@-theta) is

Prove that, sin(40^(@)+theta)cos(10^(@)+theta)-cos(40^(@)+theta)sin(10^(@)+theta)=(1)/(2)