[" If "/_ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos C);" If "b=2],[" then the area of the triangle is "]

In Delta ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos c); If b=2 'then the area of the triangle is

In Delta ABC , (a)/( cos A) = (b) /( cos B ) = ( c ) /( cos C ) , If b= 2 then the area of the triangle is

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-

in a triangle ABC , ( cos A)/(a) = (cos B )/( b) = ( cos C )/( c ) if a=(1 )/( sqrt(6)) then the area of the triangle ( in square units ) is

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

If in a triangle ABC, 2 (cos A)/(a) + (cos B)/(b) +2 (cos C)/(c) = (a)/(bc) + b/(ca) then the value of the angle A is

If in a triangle ABC, 2 (cos A)/(a) +(cos B)/(b)+2(cos C)/c=(a)/(bc)+b/(ca) then the value of the angle A is