The solution curve of the differential equation, `(1+e^(-x))(1+y^(2))(dy)/(dx)=y^(2)`, which passes through the point (0,1), is:

A solution curve of the differential equation (x^(2)+xy+4x+2y+4)(dy)/(dx)-y^(2)=0, x gt0 , passes through the point (1, 3). Then the solution curve-

The solution of the differential equation (1+y^2)+(x-e^(tan^-1 y))(dy)/(dx)=0 , is

A solution curve of the differential equation (x^(2)+xy+4x+2y+4)((dy)/(dx))-y^(2)=0 passes through the point (1,3) Then the solution curve is

The solution of the differential equation (1+e^(x))y(dy)/(dx) = e^(x) when y=1 and x = 0 is

The solution of the differential equation (1+x^(2))(1+y)dy+(1+x)(1+y^(2))dx=0

The solution of the differential equation (1 + y^(2)) + (x- e^(Tan^(-1)y)) (dy)/(dx) = 0 is

A solution curve of the differential equation (x^2+xy+4x+2y+4)((dy)/(dx))-y^2=0 passes through the point (1,3) Then the solution curve is

A solution curve of the differential equation (x^2+xy+4x+2y+4)((dy)/(dx))-y^2=0 passes through the point (1,3) Then the solution curve is