" 12."P(E)=?

If E_(1) and E_(2) are two independent events such that P(E_(1))=(1)/(2),P(E_(2))=(7)/(12),P(bar(E)_(1)nnbar(E)_(2))=(1)/(4) check whether E_(1) and E_(2) are independent events or not

P (E ) +P ( E' )=…….

If E and F are any two events such that P(E) + P(F) - P(E and F) = P(E) Then (A) P(F/E) = 1 , (B) P(E/F) = 1 , (C) P(F/E) = 0 , (D) P(E/F) = 0.

If P(E_(1)) = p_(1) and P(E_(2)) = p_(2) and E_(1) and E_(2) are independent events then P( neither E_(1) nor E_(2) )=

If P(E_(1)) = p_(1) and P(E_(2)) = p_(2) and E_(1) and E_(2) are independent then P( neither E_(1) nor E_(2) )=

A sample space consists of 9 elementary event E_1, E_2, E_3 ..... E_8, E_9 whose probabilities are P(E_1) = P(E_2) = 0. 08 , P(E_3) = P(E_4)=P(E_5) = 0. 1 , P(E_6) = P(E_7) = 0. 2 , P(E_8) = P(E_9) = 0. 07 . Suppose A = {E_1,E_5,E_8} , B = {E_2, E_5, E_8, E_9} . Compute P(A) , P(B) and P(AnnB) . Using the addition law of probability, find P(AuuB) . List the composition of the event AuuB , and calculate, P(AuuB) by adding the probabilities of the elementary events. Calculate P(barB) from P(B) , also calculate P(barB) directly from the elementary events of barB .

E and F are events such that P(E) =(1)/(3) P(F)= (1)/(4) , P(EnnF) = (1)/(5) . Find i. P(E|F) ii. P(F|E) iii. P(E uuF)

For any event E ,which of the following is correct P(E)>=0 P(E) 0 P(E)<0

If P(E)=0-8, P(F)=0.5 and P(F/E)=0.4 , then P(E/F)=