Home
Class 12
PHYSICS
In reactor 2, kg of ""(92) U^(235) fuel...

In reactor 2, kg of `""_(92) U^(235)` fuel is fully used up in 30 days . The energy released per fission is 200 MeV. Given that the Avogadro number `,N=6.023 xx 10^(26)` per kilo mole and `1e V=1.6 xx 10^(-19)J.` The power output of the reactor is close to

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the energy released by the fission 1 g of .^235U in joule, given that the energy released per fission is 200 MeV. (Avogadro.s number = 6.023 xx 10^23 )

Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))

Calculate the energy released by fission from 2g of ._(92)^(235)U in kWh. Given that the energy released per fission is 200 MeV.

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

A nuclear reactor has a power of 16 kW. If the energy released per fission is 200 MeV, the number of fissions per second is