Three positive numbers form a G.P. If the second term is increased by 8, the resulting sequence is an A.P. In turn, if we increase the last term of this A.P. by 64, we get a G.P. Find the three numbers .

Three positive numbers form a GP. If the middle number is increased by 8, the three numbers form an AP. If the last number is also increased by 64 along with the previous increase in the middle number, the resulting numbers form a GP again.Then :-

Three positive numbers from an increasing G.P. If the middle term in this G.P is double , the new numbers are in A.P then the common ratio of the G.P. is :

Three positive numbers form an increasing G.P .If the middle term in this G.P is doubled , the new numbers are in A.P .Then the common ration of the G.P is -

Three positive numbers froman increasing G.P. If middle term in this G.P. is doubled, the new numbers are in A.P. Then the common ratio of the G.P. is :

Three integers form an increasing G.P. If the third number is decreased by 16, we get an A.P. If then the second number is decreased by 2, we again get a G.P. The smallest number of the original G.P. is

The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number is reduced by 1 and the third is increased by 1, we obtain three consecutive terms of a G.P. Find the numbers.

The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number is reduced by 1 and the third is increased by 1 we obtain three consecutive terms of a G.P. Find the numbers.

The product of first three terms of a G.P. is 1000 . If we add 6 to its second term and 7 to its third term, the resulting three terms form an A.P. Find the terms of the G.P.