Let a curve passes through (3, 2) and satisfied the differential equation (x-1) dx + 4(y -2) dy = 0

A curve passes through (1,0) and satisfies the differential equation (2x cos y + 3x^2y) dx +(x^3 - x^2 siny - y)dy = 0

If a conic passes through (1, 0) and satisfies differential equation (1 + y^2) dx - xy dy = 0 . Then the foci is:

Equation of curve passing through (1, 1) and satisfying the differential equation (dy)/(dx) =(2y) /(x) , ( where x gt 0 , y gt 0 ) is given by :

Find the equation of the curve that passes through the point (1, 2) and satisfies the differential equation (dy)/(dx) =(-2xy)/((x^(2)+1)).

Consider dy/dx=-(2xy)/(x^2+1) Find the equation of the curve that passes through (1,2) and satisfies the differential equation.

The equation of the curve passing through (3,4) and satisfying the differential equation. y((dy)/(dx))^(2)+(x-y)(dy)/(dx)-x=0 can be

The equation of the curve passing through (3,4) and satisfying the differential equation. y((dy)/(dx))^(2)+(x-y)(dy)/(dx)-x=0 can be

find the equation of the curve which passes through the point (2,2) and satisfies the differential equation y-x(dy)/(dx)=y^(2)+(dy)/(dx)

A curve passes through (1,0) and satisfies the differential equation (2x cos y+3x^(2)y)dx+(x^(3)-x^(2)sin y-y)dy=0