A parallel plate capacitor has plate of length 'l' width 'w' and separation of plates is 'd' . It is connected to a battery of emf V . A dielectric slab of the same thickness 'd' and of dielectric constant k=4 is being inserted between the plates of the capacitor . At what lenght of the slab inside plates , will the energy stored in the capacitor be two time the initial energy stored ?

Figure shows a parallel-plate capacitor with plates of width b and length l. The separation between the plates is d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. Calculate the energy of the system when a length x of the slab is introduced into the capacitor.

Shown a parallel plate capacitor with plates of width b and length l . The separation between the platesis d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. (a) Calculate the energy of the system when a length x of the slab is introduced into the capacitor. (b) what force should be applied on teh slab to ensure that is goes slowly into the capacitor? Neglect any effect of friction or gravity.

Shown a parallel plate capacitor with plates of width b and length l . The separation between the platesis d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. (a) Calculate the energy of the system when a length x of the slab is introduced into the capacitor. (b) what force should be applied on the slab to ensure that is goes slowly into the capacitor? Neglect any effect of friction or gravity.

Shown a parallel plate capacitor with plates of width b and length l . The separation between the platesis d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. (a) Calculate the energy of the system when a length x of the slab is introduced into the capacitor. (b) what force should be applied on the slab to ensure that is goes slowly into the capacitor? Neglect any effect of friction or gravity.

A parallel plate capacitor (plate length L , plate width b , separation between plates d) is connected to a battery of emf V . A dielectric slab of dielectric constant K and before capacitor. Determine the force by which dielectric is attrached by capacitor.

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

A parallel-plate capacitor of plate area A and plate separation d is charged by a ideal battery of e.m.f. V and then the battery is disconnected. A slab of dielectric constant 2k is then inserted between the plates of the capacitor so as to fill the whole space between the plates. Find the change in potential energy of the system in the process of inserting the slab.

Two identical parallel plate capacitors are connected in series to a battery of 100V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively