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log""(125)/(16)=………...

`log""(125)/(16)=………`

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log_(25)(1/125) =

log((9)/(14))+log((35)/(24))-log((15)/(16))=0

The value of log ((18)/(14))+log((35)/(48))-log((15)/(16))=

Simplify: log((3)/(8)) + log ((45)/(8)) - log ((15)/(16)) .

Expand log""(343)/(125) .

log_(5)125=………..

Prove that "log" 2 + 16 "log" (16)/(15) + 12 "log " (25)/(24) + 7 "log"(81)/(80) = 1 .

log5-(log25)/(2^(2))+(log125)/(3^(2))-(log625)/(4^(2))+ ……

log5-(log25)/(2^(2))+(log125)/(3^(2))-(log625)/(4^(2))+ ……

Given log_(x)25 - log_(x) 5 = 2 - "log"_(x) (1)/(125) , find x.