A car, starting from rest, has a constant acceleration for a time interval ` t_1` during which it covers a distance In the next time interval the car has a constant retardation and comes to rest after covering a distance in time Which of the following relations is correct?

A car starts from rest and moves with constant acceleration. In first t seconds it covers distance x. Then distance covered by it in next t seconds will be:-

A train moves from rest with acceleration alpha and in time t_(1) covers a distance x. It then decelerates rest at constant retardation beta for distance y in time t_(2) . Then

An elevator accelerates from rest at a constant rate alpha for time interval t_(1) and travels a distance S_(1) It them retards at a constant rate beta for time interval t_(2) and finally comes to rest after travelling a distance S_(2) during its retardation Show that: (S_(1))/(S_(2))=(t_(1))/(t_(2))=(beta)/(alpha) .

A car starts from rest and moves with constant acceleration. The ratio of the distance covered in the nth second to that covered in n seconds is

The distance-time graph of a car which comes to a stop after covering a certain distance will be :

A car starts from rest and moves with constant acceleration. The ratio of distance covered by the car in nth second with that covered in n seconds is:

A car accelerates from rest at a constant rate a for some time after which it retards at a constant rate to come to rest. If the time elapsed is t, maximum velocity reached is

A train accelerates from rest at a constant rate α a for distance x_(1) and time t _(1) . After that is retards at constant rate beta for distance x_(2) and time t_(2) and comes to the rest. Which of the following relation is correct:-

A car starting from rest, accelerates at a constant rate x for sometime after which it decelerates at a constant rate y to come to rest. If the total time elapsed is t, the maximum velocity attained by the car is given by