(4x-5y)(16x^(2)+20xy+25y^(2))

Find the products: (4x-5y)(16 x^2+20 x y+25 y^2)

Simplify : 7x^(3)+8y^(3)-(4x+3y)(16x^(2)-12xy+9y^(2))

Let P_(1),p_(2),p_(3) be the perpendicular distance between pair of parallel lines represented by x^(2)-3x-4=0, y^(2)-5y+6=0,4x^(2)+20xy+25y^(2)=0 respectively then :

Simplify : 7x^3 +8y^3- (4x+3y)(16x^2-12xy+9y^2)

Find the product: (3x-5y-4)(9x^(2)+25y^(2)+15xy+12x-20y+16)

{:( "Column" A ,, "Column" B) , ("If" a^(2) - b^(2) = 16 "and" a- b = 2 "," "then" a + b,, "(a)" 3x^(2) - x - 11), ("The degree of " (x-a) (x-b) (x - c) (x-d) ,, "(b)" 3x^(2) - x + 5), (4x^(2) + 20xy + 25y^(2) ,, (c) 8), ((5x^(2) + 7x -3)- (2x^(2) + 8x -8) ,, (d) 4), (,, (e) (4x + 5y) (x+ 5y)), (,,(f) (2x + 5y)^(2)):}

Factorise : (i) 36x^(2)+60xy+25y^(2) (ii) (49)/(9)x^(2)-(35)/(6)xy+(25)/(16)y^(2)

Factorise : (i) 36x^(2)+60xy+25y^(2) (ii) (49)/(9)x^(2)-(35)/(6)xy+(25)/(16)y^(2)

Evaluate : 3x^(2) + 5xy - 4y^(2) + x^(2) - 8xy - 5y^(2)