[" (c) "cos^(2)alpha+cos^(2)beta+cos],[" 28."int(1)/(sin^(2)x cos^(2)x)dx" uriat "],[" (a) "tan x+cot x+c]

int(cos 2x)/(1+sin x cos x)dx

int(cos2x)/((sin x+cos x)^(2))dx=

int(cos2x)/((cos x+sin x)^(2))dx

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then (a) sin ^ (2) alpha + sin ^ (2) beta + sin ^ (2) gamma = (3) / ( 2) (b) sin ^ (2) alpha + sin ^ (2) beta + sin ^ (2) gamma = (3) / (4) (c) cos ^ (alpha) + cos ^ (2) beta + cos ^ (2) gamma = (3) / (2) (d) cos ^ (2) alpha + cos2 beta + cos2 gamma = -1

int (1)/(2 sin^(2) x + 3 sin x cos x - 2 cos^(2) x ) dx =

If int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx=a sin2x+C then a=

(i) int(cos^(3) x+ sin^(3) x)/(sin^(2) x.cos ^(2) x)dx " "(ii) int(cos2x)/(cos^(2) x sin^(2)x) dx

(i) int(cos^(3) x+ sin^(3) x)/(sin^(2) x.cos ^(2) x)dx " "(ii) int(cos2x)/(cos^(2) x sin^(2)x) dx

If (cos x-cos alpha) / (cos x-cos beta) = (sin ^ (2) alpha cos beta) / (sin ^ (2) beta cos alpha) then cos x =