(Projection Formulae) if `a ,b ,c` are the lengths of the sides opposite respectively to the angles `A ,B ,C` of a triangle `A B C ,` show that `a=bcosC+ccosB` (ii) `b=ccosA+acosC` (iii)`c=acosB+bcosA`

(Projection Formulae) if a,b,c are the lengths of the sides opposite respectively to the angles A,B,C of a triangle ABC, show that a=b cos C+cos B( ii) b=os A+a cos C( iii )c=a cos B+b cos A

(Cosine Formulae) if a ,b ,c are the lengths of the sides opposite respectively to the angles A ,B ,C of a triangle A B C , show that cosA(b^2+c^2-a^2)/(2b c) (ii) cosB(c^2+a^2-b^2)/(2a c) (iii) (i) cosC(a^2+b^2-c^2)/(2a b)

(Cosine Formulae) if a ,b ,c are the lengths of the sides opposite respectively to the angles A ,B ,C of a triangle A B C , show that (I) cosA=(b^2+c^2-a^2)/(2b c) (ii) cosB=(c^2+a^2-b^2)/(2a c) (iii) (i) cosC=(a^2+b^2-c^2)/(2a b)

(Cosine Formulae) if a,b,c are the lengths of the sides opposite respectively to the angles A,B,C of a triangle ABC, show that cos A(b^(2)+c^(2)-a^(2))/(2bc)( (ii) cos B(c^(2)+a^(2)-b^(2))/(2ac) (iii) (i) cos C(a^(2)-c^(2))/(2ab)

Show that a(bcosC -ccosB)=b^2 -c^2

For any triangle ABC, prove that a(bcosC-ccosB)=b^2-c^2

In triangle ABC , prove that c=acosB +bcosA .

Show that in any triangle ABC, a=bcosC + c.cosB

Prove that a(bcosC-ccosB)=b^2-c^2

Using vectors , prove that in a triangle ABC a = b cos C + c cos B where a,b,c are lengths of the ideas opposite to the angles A,B,C of triangle ABC respectively .