[" Let the unit vector "vec a" and "vec b" are inclined at an angle "2 theta" and "|vec a-vec b|" is less than "1" .If "0<=theta<=pi" then "theta" lies in the "],[" interval "]

If the unit vectors vec(e_(1)) and vec(e_(2)) are inclined at an angle 2theta and |vec(e_(1)) - vec(e_(2))| lt 2 , then for theta in [0,pi], theta may lie in the interval

Let the unit vectors vec a and vec b be perpendicular to each other and the unit vector vec c be inclined at an angle theta to both vec a and vec b . If vec c = x vec a + y vec b + z (vec a xx vec b) then,

If vec a and vec b are unit vectors find the angle between vec a+vec b and vec a-vec b

vec a and vec b are inclined at an angle theta=30^(@) If |vec a|=1,|vec b|=2 then |(vec a+3vec b)xx(3vec a-vec b)|^(2)=

If vec a and vec b are unit vectos inclined at an angle theta then the value of |vec a-vec b| is 2(sin theta)/(2) b.2sin theta c.2(cos theta)/(2) d.2 cos

If unit vectors hat(a) and hat(b) are inclined at angle theta , then prove that |vec(a) - vec(b)| = 2 sin.(theta)/(2) .

Let the unit vectors vec a and vec b be perpendicular to each other and the unit vector vec c be inclined at an angle theta to both vec a . and vec b. If vec c=xvec a+yvec b+z(vec a xxvec b) then

If vec a and vec b are unit vectors,and theta is the angle between them,then |vec a-vec b|=

If vec a and vec b are unit vectors |vec a xx vec b| =1 then the angle between vec a and vec b is