The shapes of `PCl_4^+, PCl_4^-` and `AsCl_4` are respectively :

The shapes of PCl_4^+ , PCl_4^- and AsCl_5 are respectively

The shape of PCl_5 is

The shape of PCl_5 is

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The oxidation number of P in PCl_5 .PCl_4^+ and PCl_6^- are respectively :

Read the following short write-up and answer the questions at the end of it. In certain polar solvents PCl_(5) undergoes an ionisation reaction in which Cl^(-) ion leaves one PCl_(5) molecule and attach itself to another. 2PCl_(5)rarrPCl_(4)^(+)+PCl_(6)^(-) Number of lone pairs around phosphorus in PCl_(5),PCl_(4)^(+) and PCl_(6)^(-) are respectively :

In the reaction PCl_5(g)⇔PCl_3(g)+Cl_2(g) the equilibrium concentration of PCl5 and PCl3 are 0.4 and 0.2 mole/litre respectively. If the value of KC is 0.5 what is concentration of Cl_2 in moles/litre ?

In the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) , the equilibrium concentrations of PCl_(5) and PCl_(3) are 0.4 and 0.2 mole // litre respectively. If the value of K_(c) is 0.5 , what is the concentration of Cl_(2) in moles // litre ?

Shape of PCl_5 molecule is