ट्रान्सफॉर्मर किसे कहते है ? इनके प्रकार लिखिए तथा सिद्ध कीजिए कि `(N_(s))/(N_(p))=(E_(s))/(E_(p))=(I_(p))/(I_(s))=K` जहाँ K ट्रान्सफॉर्मर का परिणमन अनुपात है।

The relation (E_(s))/(E_(P)) = (n_(s))/(n_(P)) is applicable only be

Using the equation of power for an ideal transformer, prove (I_(p))/( I_(s)) = ( V_(s))/( V_(p)) = ( N_(s))/( N_(p))

A transformer is an electrical device which is used for changing the a.c. voltage. It is based on the phenomenon of mutual induction. It can be shown that (E_(s))/(E_(P)) = (I_(P))/(I_(s)) = (n_(s))/(n_(P)) = K Where the symbols have their standard meaning. For a step up transformer, K gt 1 and for a step down transformer, K lt 1 . The above relations are on the assumption that efficiency of transformer is 100% . In fact, efficiency eta = ("output power")/("input power") = (E_(s) I_(s))/(E_(P) I_(P)) The number of turns in the primary and secondary coils of a transformer are 2000 and 50 respectively. The primary coil is connected to main supply of 120 V and secondary to a night bulb 0.6 Omega . The efficiency of transformer is 80% . Current in primary coil is:

A transformer is an electrical device which is used for changing the a.c. voltage. It is based on the phenomenon of mutual induction. It can be shown that (E_(s))/(E_(P)) = (I_(P))/(I_(s)) = (n_(s))/(n_(P)) = K Where the symbols have their standard meaning. For a step up transformer, K gt 1 and for a step down transformer, K lt 1 . The above relations are on the assumption that efficiency of transformer is 100% . In fact, efficiency eta = ("output power")/("input power") = (E_(s) I_(s))/(E_(P) I_(P)) The number of turns in the primary and secondary coils of a transformer are 2000 and 50 respectively. The primary coil is connected to main supply of 120 V and secondary to a night bulb 0.6 ohm . The efficiency of transformer is 80% . Current in night bulb is:

A transformer is an electrical device which is used for changing the a.c. voltage. It is based on the phenomenon of mutual induction. It can be shown that (E_(s))/(E_(P)) = (I_(P))/(I_(s)) = (n_(s))/(n_(P)) = K Where the symbols have their standard meaning. For a step up transformer, K gt 1 and for a step down transformer, K lt 1 . The above relations are on the assumption that efficiency of transformer is 100% . In fact, efficiency eta = ("output power")/("input power") = (E_(s) I_(s))/(E_(P) I_(P)) The number of turns in the primary and secondary coils of a transformer are 2000 and 50 respectively. The primary coil is connected to main supply of 120 V and secondary to a night bulb 0.6 Omega . The efficiency of transformer is 80% . Power in primary coil is:

A transformer is an electrical device which is used for changing the a.c. voltage. It is based on the phenomenon of mutual induction. It can be shown that (E_(s))/(E_(P)) = (I_(P))/(I_(s)) = (n_(s))/(n_(P)) = K Where the symbols have their standard meaning. For a step up transformer, K gt 1 and for a step down transformer, K lt 1 . The above relations are on the assumption that efficiency to transformer is 100% . In fact, efficiency eta = ("output power")/("input power") = (E_(s) I_(s))/(E_(P) I_(P)) The number of turns in the primary and secondary coils of a transformer are 2000 and 50 respectively. The primary coil is connected to main supply of 120 V and secondary to a night bulb 0.6 Omega . The efficiency of transformer is 80% . Power in secondary coil is:

A transformer is an electrical device which is used for changing the a.c. voltage. It is based on the phenomenon of mutual induction. It can be shown that (E_(s))/(E_(P)) = (I_(P))/(I_(s)) = (n_(s))/(n_(P)) = K Where the symbols have their standard meaning. For a step up transformer, K gt 1 and for a step down transformer, K lt 1 . The above relations are on the assumption that efficiency of transformer is 100% . In fact, efficiency eta = ("output power")/("input power") = (E_(s) I_(s))/(E_(P) I_(P)) The number of turns in the primary and secondary coils of a transformer are 2000 and 50 respectively. The primary coil is connected to main supply of 120 V and secondary to a night bulb 0.6 Omega . The efficiency of transformer is 80% . Voltage across the secondary coil of transformer is: