In `DeltaABC`, `E` is the midpoint of the median `AD`. `BE` produced meets `AC` at `F`. Prove that `AF=(1/3)AC`

E is the middle point of the median AD of /_\ABC . BE produced meets AC at F. Prove that CA=3AF .

E is the middle point of the median AD of /_\ABC . BE intersects AC at F. Prove that AF=1/3AC .

In A ABC, E is mid-point of the median AD and BE produced meets side AC at point Q. Show that BE : EQ = 3:1.

In triangleABC, AD is the median through A and E is the mid point of AD. BE is produced so as to meet AC in F. prove that AF=1/3AC

In ABC,AD is the median through A and E is the mid-point of AD.BE produced meets AC in F (Figure).Prove that AF=(1)/(3)AC .

In Delta ABC , AD is a median and E is the midpoint of AD. BE is extended to intersect AC at F. Prove that AF = (1)/(3)AC .

In the fig. AD is a median of triangle ABC and E is the mid point of AD, also BE meets AC in F. prove that AF=1/3AC

E is the mid-point of AD , a median of the Delta ABC . The extended BE intersects AC at F. prove that AF=(1)/(3)AC.

In the given figure, ABCD is a parallelogram and E is the midpoint of side BC. If DE and AB when produced meet at F, prove that AF = 2AB.

In a triangle ABC, AD is a median and E is mid-point of median AD. A line through B and E meets AC at point E. Prove that : AC = 3AF Draw DG parallel to BF, which meets AC at point G.