(1-1/(1!) +9/(2!) +(27)/(3!) + .....oo) ...

`(1-1/(1!) +9/(2!) +(27)/(3!) + .....oo) (1+9/(1!) +(81)/(2!)+(729)/(3!)+ .....oo)`=

`e^2`

`e^3`

`e^6`

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The correct Answer is:

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