A : The value of e lies between 2 and 3....

A : The value of e lies between 2 and 3.
R : `e=1+(1)/(1!)+(1)/(2!)+(1)/(3!)+....`

A is true, R is true and R is correct explanation of A

A is true, R is true and R is not correct explanation of A

A is true , R is false

A is false, R is true

Verified by Experts

The correct Answer is:

EXPONENTIAL SERIES
AAKASH SERIES|Exercise EXERCISE - II (A) (CLASS WORK)|40 Videos
EXPONENTIAL SERIES
AAKASH SERIES|Exercise EXERCISE - II (A) (HOME WORK)|30 Videos
EXPONENTIAL SERIES
AAKASH SERIES|Exercise EXERCISE - III|8 Videos
ELLIPSE
AAKASH SERIES|Exercise PRACTICE EXERCISE|65 Videos
HYPERBOLA
AAKASH SERIES|Exercise Exercise|6 Videos

1+(log(e)5)/(1!) +(loge5)^2/(2!)+(loge5)^3/(3!)+ .......oo =
Text Solution
|
1-log2+((log2)^2)/(2!) -(log2)^3/(3!)+....oo
Text Solution
|
1+ 2 (logeq)+(2^2)/(2!) (logea)^2 +(2^3)/(3!) (loge a)^3+...=
Text Solution
|
(1/(1!) +1/(2!) +1(3!) + .....oo) (1/(2!) +1/(3!) +1(4!)-1/(5!) .....o...
Text Solution
|
(1-1/(1!) +9/(2!) +(27)/(3!) + .....oo) (1+9/(1!) +(81)/(2!)+(729)/(3!...
Text Solution
|
sum(n=1) ^(oo) (1)/((2n-1)!)=
Text Solution
|
e^(7x)-e^(-7x)=
Text Solution
|
The 12th term in the expansion of e^(-3) is
Text Solution
|
Coffiecient of x^3 in the expansion of e^(-bx)
Text Solution
|
A : The value of e lies between 2 and 3. R : e=1+(1)/(1!)+(1)/(2!)+(...
Text Solution
|

Similar Questions