If a=sum(n=1)^(oo)((2n))/(2n-1),b sum(n=...

If `a=sum_(n=1)^(oo)((2n))/(2n-1),b sum_(n=1)^(oo) (2n)/(2n+1!)` then ab =

`e^2`

`(e-1)/(e+1)`

`(e+1)/(e-1)`

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sum(n=0)^(oo)((loge x)^(2n))/((2n)!)=
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