sum(n=1)^(oo) ((logex)^(2n-1))/((2n-1)!)...

`sum_(n=1)^(oo) ((log_ex)^(2n-1))/((2n-1)!)=`

`x+!`

`x-1`

`x^2-1`

`(x^2-1)/(2x)`

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The correct Answer is:

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