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If the the angle between the circles x...

If the the angle between the circles
`x^2+y^2-12x-6y+41=0` and `x^2+y^2+kx+6y-59=0` is `45^@` find k.

Answer

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If the angle between the circles x^2 + y^2 - 12x - 6y + 41 = 0 and x^2 + y^2 + kx + 6y - 59 = 0 is 45^@ find k.

Find the angle between the circles x^(2)+y^(2)=12x-6y+41=0, x^(2)+y^(2)+4x+6y-59=0

Knowledge Check

  • The angle between the circles x^2+y^2-2x-4y+3=0 and x^2+y^2-4x-6y+11=0 is

    A
    `pi/4`
    B
    `pi/6`
    C
    `pi/2`
    D
    `(2pi)/3`

  • The angle between the circles x^2+y^2+4x+8y+18=0 and x^2+y^2+2x+6y+8=0 is

    A
    `pi/4`
    B
    `(2pi)/3`
    C
    `pi/6`
    D
    `pi/2`

  • The angle between the circles x^(2)+y^(2)-4x-6y-3=0 ," x^(2)+y^(2)+8x-4y+11=0 " is

    A
    `pi//3`
    B
    `pi//2`
    C
    `pi//5`
    D
    `pi//4`

    • Similar Questions

    Explore conceptually related problems

    Find the angle between the circles given by the equations. x^2 + y^2 - 12x - 6y + 41 = 0, x^2 + y^2 + 4x + 6y - 59 = 0.

    The circle x^(2)+y^(2)-4x-6y-12=0, x^(2)+y^(2)+6x-8y+21=0 are

    The radical centre of the circles x^2+y^2=9, x^2+y^2-2x-2y-5=0 , x^2+y^2+4x+6y-19=0 is

    The equation of the circle passing through (1,2) and the points of intersection of the circles x^2+y^2-8x-6y+21=0 and x^2+y^2-2x-15=0 is

    The locus of the centre of the circle cutting the circles x^2+y^2–2x-6y+1=0, x^2 + y^2 - 4x - 10y + 5 = 0 orthogonally is

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