Home
Class 12
MATHS
Find the equation of the circle which pa...

Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally.
`x^2+y^2-4x-6y-3=0`
`x^2+y^2-8y+12=0`

Text Solution

Verified by Experts

The correct Answer is:
`2(x^2+y^2)-7x+2y=0`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SYSTEM OF CIRCLES

    AAKASH SERIES|Exercise Exercise -2.2 (Very Short Answer)|9 Videos

  • SYSTEM OF CIRCLES

    AAKASH SERIES|Exercise Exercise -2.2 (Short Answer)|5 Videos

  • SYSTEM OF CIRCLES

    AAKASH SERIES|Exercise Exercise -2.1 (Short Answer)|11 Videos

  • STRAIGHT LINES (3D)

    AAKASH SERIES|Exercise PRACTICE EXERCISE|28 Videos

  • THEORY OF EQUATIONS

    AAKASH SERIES|Exercise EXERCISE-III|46 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally. x^(2)+y^(2)-4x+6y+10,x^(2)+y^(2)+12y+6=0

Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally. x^2 + y^2 - 4x - 6y - 3 = 0 . x^2 + y^2 - 8y + 12 = 0 .

Knowledge Check

  • The equation of the circle which passes through the origin has its centre on the line x+y=4 and cuts orthogonally the circle x^2+y^2-4x+2y+4=0

    A
    `x^2+y^2-4x-4y=0`
    B
    `x^2+y^2-2x-6y=0`
    C
    `x^2+y^2-6x-2y=0`
    D
    `x^2+y^2+4x-12y=0`

    • Similar Questions

    Explore conceptually related problems

    Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally. x^2 + y^2 - 4x + 6y + 10 = 0 . x^2 + y^2 + 12y + 6 = 0 .

    The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^2+y^2-6x+8=0 and x^2+y^2-2x-2y=7 is

    Find the equation of the circle which intersects each of the following circles orthogonlly x^2 + y^2 + 4x + 2y + 1 = 0 . 2(x^2 + y^2) + 8x + 6y - 3 = 0, x^2 + y^2 + 6x -2y - 3 =0.

    Find the equation of the circle which cuts each of the following circles orthogonally. x^2+y^2+2x+4y+1=0 2x^2+2y^2+6x+8y-3=0 x^2+y^2-2x+6y-3=0

    Find the equation of the circle which passes through the point (0,-3) and intersect the circles given by the equations x^2+y^2-6x+3y+5=0 and x^2+y^2-x-7y=0 orthogonally .

    Find the equation of the circle which passes through the point (0,-3) and intersects the circles given by the equation x^2 + y^2 - 6x + 3y + 5 = 0 and x^2 + y^2 - x - 7y = 0 orthogonally.

    Find the equation of the circle which cuts each of the following circles orthogonally. x^2+y^2+3x+2y+1=0 x^2+y^2-x+6y+5=0 x^2+y^2+5x-8y+15=0

    Home
    Profile