Home
Class 12
MATHS
Find k if the following pairs of circles...

Find k if the following pairs of circles are orthogonal
`x^2+y^2-6x-8y+12=0`
`x^2+y^2-4x+6y+k=0`

Text Solution

Verified by Experts

The correct Answer is:
`x^2+y^2+6x-3y=0`
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF CIRCLES

    AAKASH SERIES|Exercise Exercise -2.2 (Very Short Answer)|9 Videos
  • SYSTEM OF CIRCLES

    AAKASH SERIES|Exercise Exercise -2.2 (Short Answer)|5 Videos
  • SYSTEM OF CIRCLES

    AAKASH SERIES|Exercise Exercise -2.1 (Short Answer)|11 Videos
  • STRAIGHT LINES (3D)

    AAKASH SERIES|Exercise PRACTICE EXERCISE|28 Videos
  • THEORY OF EQUATIONS

    AAKASH SERIES|Exercise EXERCISE-III|46 Videos

Similar Questions

Explore conceptually related problems

Find k if the following pairs of circles are orthogonal x^(2)+y^(2)-6x-8y+12=0,x^(2)+y^(2)-8x+6y+k=0

Find k if the following pairs of circles are orthogonal x^2+y^2-16y-k=0 x^2+y^2+4x-8=0

Find k if the following pairs of circles are orthogonal. x^2 + y^2 + 4x + 8 = 0, x^2 + y^2 - 16y + k = 0

Find k if the following pairs of circles are orthogonal x^2+y^2+2by-k=0 x^2+y^2+2ax+8=0

Find k if the following pairs of circles are orthogonal. x^2 + y^2 - 5x - 14y - 34 = 0. x^2 + y^2 + 2x + 4y + k = 0

Find k if the following pairs of circles are orthogonal x^(2)+y^(2)-16y+k-0, x^(2)+y^(2)+4x+8=0

Find k if the following pairs of circles are orthogonal. x^2 + y^2 + 2by - k = 0, x^2 + y^2 + 2ax + 8 = 0 .

Find the number of possible common tangent that exits for the following pairs of circle. (a) x^(2) + y ^(2) -4x -2y +1= 0, x^(2) +y^(2) -6x -4y +4=0 (b) x^(2) + y ^(2) -4 x + 2y -4=0 , x^(2) + y ^(2) + 2x - 6y + 6=0

Find the equation of the common chord of the following pair of circles. x^2 + y^2 - 4y + 3 = 0 , x^2 + y^2 - 5x - 6y + 4 = 0 .