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Show that the equation of the line passsing through the points of intersection of the circles `3x^2+3y^2-2x+12y-9=0` and `x^2+y^2+6x+2y-15=0` is `10x-3y-18=0`

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The correct Answer is:
`3(x^2+y^2)-18x-12y+27=0`
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