A particle travels from point A to B on a circular path of radius 15/`pi` cm.If the are length AB be 10 cm,find the displacement (figure)

Explanation

joining the initial (A)and final (B) positions of the body,the straight line AB is obtained which is its displacement (figure)
We know,
`("circumference")/("are lengh")=(360^(@))/("Angle subtended by are at centre")`
`therefore(2pixx(15)/(pi))/(10)=(360^(@))/(20)`
`implies20theta=120^(@)impliestheta=60^(@)`
AD=OA sin `theta=(15)/(pi)sin60^(@)=(15sqrt(3))/(2pi)`
`therefore AB=2AD=(15sqrt(3))/(pi)`cm along A to B