Velocity of a particle moving in a straight line varies with its displacement as v=`(sqrt(4+4s))` m/s.Find its displacement I the first 2 seconds of its motion.

Explanation

Squating the given equation ,we get `v^(2)`=4+4s
Now,Comparing it with `v^(2)=u^(2)+2as`
We get,u=2m/s and a=2 m/ `s^(2)`
Therefore,Displacement t=2s is
`S=ut+(1)/(2)at^(2)` or s=(2)`(2)^(2)` or s=8 m