Two cars started simultaneously towards each other from towns A and B which are 480 km apart.It took first car travelling from A to B 8 hours to cover the distance and second car travelling form B to A in 12 hours.Determine when do the car meet after starting and at what distance from town A.Assuming that both the cars travelled with constant speed.

Explanation

Velocity of car from `A=(480)/(8)=60 km//hour`
Distance travelled from A =60 t velocity of car from `B=(480)/(12)=40 km/hour`
Distance travelled from B=40 t
Let the two cars meet at t hour then 60 t+40 t=480 km
`therefore t=(480)/(60+40)=4.8 hours`
The distance s=`v_(a)xxt=6-xx4.8=288km`