A particle P is projected vertically upward from a point A. Six seconds later, another particle Q is projected vertically upward from A. Both P and Q reach A simultaneously. The ratio of maximum heights reached by P and Q=64:25.Find the velocity of the projection of Q in m/s.

Explanation

`(1)/(2) g(t+3)^(2),(1)/(2) "gt"^(2)=64:25` (or)
`(t+3)^(2):t^(2)`=64:25,(or) (t+3):t=8,5
5t+15=8t (or) 3t =15,t=5 sec
`v=gxxt=9.8xx5=49 m//s=5g m//s`