A body when projected vertically up,covers a total distance D .During the time of its flight.If there were no gravity,find the distance covered by it during the same time .

Explanation

The displacement of the body during the time t as it attains the point of projection
`impliesS=0`
`impliesv_(0)t-(1)/(2)"gt"^(2)=0`
`impliest=(2v_(0))/((g)`
During the same time t ,the body moves in absence of gravity through a distance `D.=v_(0)t`, becuase is absence of gravity g=0
`impliesDv_(0)((2v_(0))/(g))=(2v_(0)^(2)0)/(g)` .......(i)
In presence of gravity the total distance covered is
`=D=2H2(v_(0)^(2))/(2g)=(v_(0)^(2))/(g)` .......(i)
In presence of gravity the total distance covered is
D=2H`=2(v_(0)^(2))/(2g)=(v_(0)^(2))/(g) `.........(ii) (i)+(ii)`implies2D`