Two particles 1 and 2 are allowed to descend on the two fricitionless chord OA and OB of a vertical circle,at the same instant from point O.The ratio of the velocities of the particles 1 and 2 respectively,when they reach on the circumference will be (OB is the dianeter)

Explanation

OA=d cos `alpha,a_(OA)`=g cos `alpha`
Along OA`impliesV_(A)^(2)`=2g cos `alpha`.d cos `alpha`
Along OB
`V_(b)^(2)=2gdimplies(V_(A))/(V_(B))`=cos `alpha`