The acceleration of a particle is given by a (t)=(3.00 `m//s^(2)-(2.00 m/s^(3))`)t. (a) Find the initial speed `v_(0)` such that the particle will have the same x -coordinate at t =5.00 as it had at t=0. (b)What will be the velocity at t =5.00s?

Explanation

(a)0.833 m/s (b)-9.17 m/s