The path of a projectile is given by the equation `y = ax – bx^(2)`, where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively.

Options

A. `(2a^2)/(b), tan^(-1) (a)`
B. `(b^2)/(2a), tan^(-1) (b) `
C. `(a^2)/(b), tan^(-1) (2b)`
D. `(a^2)/(4b) , tan^(-1) (a)`

Answer

D