A particle moves in a circular path such that its speed v varies with distance as `v= alpha sqrt(s)` where `alpha` is a positive constant. Find the acceleration of particle after trafversing a distance S?

Options

A. `alpha sqrt(1/4 - (S^2)/(R^2))`
B. `alpha sqrt(1/4 + (S^2)/(R^2))`
C. `alpha sqrt(1/2 + (S^2)/(R^2))`
D. `alpha^2 sqrt(1/2 + (S^2)/(R^2))`

Answer

B