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Two particles of masses m(1) and m2 in ...

Two particles of masses `m_(1)` and `m_2` in projectile motion have velocities `vecv_(1)` and `vecv_(2)` respectively at time t = 0. They collide at time `t_(0)`. Their velocities become `vecv_(1)` and `vecv_(2)` at time `2t_(0)` while still moving in air. The value of `|(m_(1)vecv_(1) + m_(2)vecv_(2)) -(m_(1)vecv_(1) + m_(2)vecv_(2))|` is

A

zero

B

`(m_1 + m_2) g t_0`

C

`2(m_1 + m_2)g t_0`

D

`1/2 (m_1 + m_2) g t_0`

Text Solution

Verified by Experts

The correct Answer is:
C
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