A helicopter of mass 1000 kg rises with vertical acceleration of `15 ms^(-2)`. The crew and the passengers weight 300 kg. Given the magnitude and direction of the
(a) force on the floor by the crew and passengers
(b) action of the rotor of the helicopter on the surrounding air
(c ) force on the helicopter due to the surrounding air.

Explanation

Here, mass of the helicopter, `m_(1)=1000 kg`
Mass of the crew and passengers
`m_(2)=300 kg`
Upward acceleration `a = 15 ms^(-2)` and `g=10 ms^(-2)`
(a) Force on the floor of helicopter by the crew and passenger = appeared weight of crew and passengers
`= m_(2)(g+a)`
`=(1000+300)(10+15)`
`=1300xx25=32500 N`
(c ) Force on the helicopter due to surrounding air is the reaction. As action and reaction are equal and opposite, therefore, force of reaction `F^(1)=32500 N`, vertically upwards.